A train moves past a post and a platform 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?
Let the length of the train be x metres and its speed by y m/sec.
Then, x =8
x + 264 =
20 x = 8y 8y + 264 = 20y
y = 22. Speed = 22 m/sec = 18
22 x 5 km/hr = 79.2 km/hr.
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Sep 13, 2020EXPERT
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